document.write( "Question 731340: Maria's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Maria 4.30 per pound, and type B coffee costs 5.40 per pound. This month, Maria made 167 pounds of the blend, for a total cost of 825.90 . How many pounds of type A coffee did she use? \n" ); document.write( "
Algebra.Com's Answer #447101 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! ASSIGN VARIABLES \n" ); document.write( "L=4.30 dollars per pound, type A \n" ); document.write( "H=5.40 dollars per pound, type B \n" ); document.write( "C=825.90 dollars cost of blend typeA+typeB \n" ); document.write( "u=unknown pounds of type A \n" ); document.write( "v=unknown pounds of type B \n" ); document.write( "M=167 pounds blend typeA+typeB\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "MAKE SYSTEM OF EQUATIONS \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "SOLVE FOR UNKNOWN VARIABLES \n" ); document.write( "Easiest may be use the material sum equation to get a formula for either u or v and substitute this expression into the cost equation and solve for the other variable; and then use the resulting formula in the material sum equation again to solve for a formula for the first variable. The system is already two equations with two unknowns, and these equations are linear.\r \n" ); document.write( "\n" ); document.write( "Since we are asked to find how much of type A coffee, ... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "You continue from here.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "COMPUTE VALUES FOR UNKNONWS \n" ); document.write( "Substitute the values to find the values for u and v. \n" ); document.write( " |