document.write( "Question 64075: 4x+27=3x \n" ); document.write( "

Algebra.Com's Answer #44709 by praseenakos@yahoo.com(507) $\"\"$ $\"About$

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QUESTION:\r
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\n" ); document.write( "\n" ); document.write( "4x+27=3x\r
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\n" ); document.write( "\n" ); document.write( "4x+27=3x\r
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\n" ); document.write( "\n" ); document.write( "Subtract 3x from both sides of the equation.\r
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\n" ); document.write( "\n" ); document.write( "==> 4x + 27 -3x = 3x - 3x\r
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\n" ); document.write( "\n" ); document.write( "==> 4x - 3x + 27 = 0\r
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\n" ); document.write( "\n" ); document.write( "==> 1x + 27 = 0\r
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\n" ); document.write( "\n" ); document.write( "Subtract 27 from both sides,\r
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\n" ); document.write( "\n" ); document.write( "==> x + 27 - 27 = 0 - 27\r
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\n" ); document.write( "\n" ); document.write( "==> x = -27\r
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\n" ); document.write( "\n" ); document.write( "Which is the required solution.\r
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\n" ); document.write( "\n" ); document.write( "Hope you understood.\r
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\n" ); document.write( "\n" ); document.write( "Regards.\r
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\n" ); document.write( "\n" ); document.write( "praseenakos@yahoo.co.in\r
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