document.write( "Question 731276: \"The perimeter of a rectangle is 36 m. The area is 65 m^2. Find the dimensions of the rectangle.\"\r
\n" ); document.write( "\n" ); document.write( "I'm supposed to use the Quadratic formula in this somehow, but I don't really understand how I get A, B, and C from this. I tried to do it, and I confused myself halfway through it. Thank you for your help!
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Algebra.Com's Answer #447070 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
What are A, B, and C supposed to be?\r
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\n" ); document.write( "\n" ); document.write( "Just use what you know about a rectangle and the given information about the problem. \r
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\n" ); document.write( "\n" ); document.write( "Let's say w = width of the rectangle and h = height of the rectangle.
\n" ); document.write( "Perimeter is 2w+2h=36.
\n" ); document.write( "Area is wh=65.\r
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\n" ); document.write( "\n" ); document.write( "Pick one of the equations, any one of them. Solve for one of the variables, w or h; it does not matter which. Substitute that formula into the other equation. Now you should have what will be a quadratic equation. You may need to simplify it before using it. \r
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\n" ); document.write( "\n" ); document.write( "A possible way to go,
\n" ); document.write( "\"2h%2B2w=36\"
\n" ); document.write( "\"2h=36-2w\"
\n" ); document.write( "\"h=18-w.\"
\n" ); document.write( "-------------
\n" ); document.write( "\"wh=65\", to continue starting with area relationship
\n" ); document.write( "\"w%2818-w%29=65\", substituting what was found for h
\n" ); document.write( "\"18w-w%5E2=65\"
\n" ); document.write( "\"-w%5E2%2B1w8=65\"
\n" ); document.write( "\"-w%5E2%2B18w-65=0\"
\n" ); document.write( "\"highlight%28w%5E2-18w%2B65=0%29\"
\n" ); document.write( "You can certainly use the general solution to quadratic formula if you want to but that polynomial seems factorable. I will use quadratic formula solution.\r
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\n" ); document.write( "\n" ); document.write( "\"w+=+%2818%2Bsqrt%2818%5E2-4%2A65%29%29%2F2\"
\n" ); document.write( "\"w=%2818%2Bsqrt%2864%29%29%2F2\"
\n" ); document.write( "\"w=%2818%2B8%29%2F2\"
\n" ); document.write( "\"highlight%28w=13%29\"
\n" ); document.write( "OR
\n" ); document.write( "\"w=%2818-sqrt%2818%5E2-4%2A65%29%29%2F2\"
\n" ); document.write( "\"w=%2818-8%29%2F2\"
\n" ); document.write( "\"highlight%28w=5%29\"\r
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\n" ); document.write( "\n" ); document.write( "That was for w. You can then use either the perimeter equation or the area equation to find h.\r
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\n" ); document.write( "\n" ); document.write( "postnote: You probably meant Ax^2+Bx+C=0 when you mentioned some confusion about \"A, B, and C\".
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