document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=731276>Question 731276</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"The perimeter of a rectangle is 36 m. The area is 65 m^2. Find the dimensions of the rectangle.\"\r<BR>\n" );
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document.write( "I'm supposed to use the Quadratic formula in this somehow, but I don't really understand how I get A, B, and C from this. I tried to do it, and I confused myself halfway through it. Thank you for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447067 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447067\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2l+2w=36<BR>\n" );
document.write( "l=65/w<BR>\n" );
document.write( "2*(65/w)+2w=36<BR>\n" );
document.write( "65/w+w-36=0<BR>\n" );
document.write( "65+w^2-36w=0<BR>\n" );
document.write( "w^2-18w+65=0<BR>\n" );
document.write( "factor<BR>\n" );
document.write( "(w-5)*(w-13)=0\r<BR>\n" );
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document.write( "w = 5<BR>\n" );
document.write( "width is shorter than length<BR>\n" );
document.write( "l=13 </SPAN>\n" );
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