document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64034>Question 64034</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Paul invested $12,000 some at 14% annual interest and the rest at 10%.  Last year he earned $1632 in interest.  How much money was invested at each rate?\r<BR>\n" );
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document.write( "Thanks so much for any help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44702 by </B><A HREF=/tutors/aboutme.mpl?userid=jai_kos><B>jai_kos(139)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jai_kos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> suppose $x is invested at 14% annual interest<BR>\n" );
document.write( " interest after 1 year = $(14x)/100<BR>\n" );
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document.write( "rest $(12000-x)at 10% annual interest<BR>\n" );
document.write( " interest after 1 year =$(12000-x)10/100<BR>\n" );
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document.write( "  by the problem 14x/100 + (12000-x)10/100 =1632<BR>\n" );
document.write( "             or   14x/100 +  1200 -10x/100 =1632<BR>\n" );
document.write( "             or   4x/100=1632-1200=432<BR>\n" );
document.write( "             or   x/25=432<BR>\n" );
document.write( "             or   x=432*25= 10800\r<BR>\n" );
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document.write( "ans: $10800 is invested at 14%<BR>\n" );
document.write( "     $(12000-10800)=$1200  is invested at 10%  </SPAN>\n" );
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