document.write( "Question 731087: a mother is 21 years older than her new born daughter how will the daughter be when her age is 1/4 that of her mother's? \n" ); document.write( "

Algebra.Com's Answer #446983 by josmiceli(19441) $\"\"$ $\"About$

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The difference in their ages will always be $\"+21+\"$ years
\n" ); document.write( "So the mother's age is always $\"+d+%2B+21+\"$
\n" ); document.write( "Let $\"+d+\"$ = daughter's age when her age is 1/4 that of her mother's
\n" ); document.write( " $\"+d+=+%281%2F4%29%2A%28+d+%2B+21+%29+\"$
\n" ); document.write( " $\"+4d+=+d+%2B+21+\"$
\n" ); document.write( " $\"+3d+=+21+\"$
\n" ); document.write( " $\"+d+=+7+\"$
\n" ); document.write( "The daughter will be 7 when her age is 1/4 that of her mother's
\n" ); document.write( "check:
\n" ); document.write( "Mother will be $\"+7+%2B+21+=+28+\"$
\n" ); document.write( "and $\"+7+=+%281%2F4%29%2A28+\"$
\n" ); document.write( "OK \n" ); document.write( "

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