document.write( "Question 730994: During the first part of a canoe trip, Ken covered 60 km at a certain speed. He then traveled 24 km at a speed that was 4 km/h slower. If the total time for the trip was 8 hr, what was the speed on each part of the trip? \n" ); document.write( "
Algebra.Com's Answer #446978 by mananth(16946)\"\" \"About 
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First Part 60 km
\n" ); document.write( "Second Part 24 km
\n" ); document.write( "
\n" ); document.write( "First Part x mph
\n" ); document.write( "Second Part x -4 mph
\n" ); document.write( "Total time 8 hours
\n" ); document.write( "First Part time 60 / x
\n" ); document.write( "Second Part time 24 / ( x -4 )
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\n" ); document.write( "Time first part + time second part = 8 hours
\n" ); document.write( "
\n" ); document.write( "60 / x + 24 /(x -4 ) = 8
\n" ); document.write( "LCD = ( x)* (x -4 )
\n" ); document.write( "multiply the equation by the LCD
\n" ); document.write( "we get
\n" ); document.write( " = 8
\n" ); document.write( "60 x -240 + )+ 24 x = 8 X^2 -32 x
\n" ); document.write( "116 x-240 = 8 X^2 = 0
\n" ); document.write( "8 X^2 -116 x+ 240 = 0
\n" ); document.write( "8 X^2+ -116 x+ 240 =
\n" ); document.write( "/ 8
\n" ); document.write( "8 X^2 -116 x+ 240 =0
\n" ); document.write( "
\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 8 b= -116 c= 240
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\n" ); document.write( "b^2-4ac= 13456 - 7680
\n" ); document.write( "b^2-4ac= 5776 \"sqrt%28%095776%09%29\"= 76 OK 5
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\" )/
\n" ); document.write( "x1=( 116 + 76 )/ 16
\n" ); document.write( "x1= 12
\n" ); document.write( "x2=( 116 - 76 )/ 16
\n" ); document.write( "x2= 2.5
\n" ); document.write( "Ignore 2.5
\n" ); document.write( "x = 12 kph
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