document.write( "Question 731055: five years ago, the director was 3 times older than one of the youngest student, now their combined ages amount to 110 years thus, the present age of the director is?\r
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Algebra.Com's Answer #446975 by mananth(16946)\"\" \"About 
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student's age =x\r
\n" ); document.write( "\n" ); document.write( "5 years ago
\n" ); document.write( "student's age x-5
\n" ); document.write( "director's age =3(x-5)\r
\n" ); document.write( "\n" ); document.write( "now student's age =x
\n" ); document.write( "director's age = 3(x-5)-5\r
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\n" ); document.write( "\n" ); document.write( "x+3(x-5)+5=110\r
\n" ); document.write( "\n" ); document.write( "x+3x-15+5=110
\n" ); document.write( "4x-10=110
\n" ); document.write( "4x=120
\n" ); document.write( "x=30 student's age now
\n" ); document.write( "plug x to get director's age
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