document.write( "Question 731055: five years ago, the director was 3 times older than one of the youngest student, now their combined ages amount to 110 years thus, the present age of the director is?\r
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Algebra.Com's Answer #446975 by mananth(16946)![]() ![]() You can put this solution on YOUR website! student's age =x\r \n" ); document.write( "\n" ); document.write( "5 years ago \n" ); document.write( "student's age x-5 \n" ); document.write( "director's age =3(x-5)\r \n" ); document.write( "\n" ); document.write( "now student's age =x \n" ); document.write( "director's age = 3(x-5)-5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+3(x-5)+5=110\r \n" ); document.write( "\n" ); document.write( "x+3x-15+5=110 \n" ); document.write( "4x-10=110 \n" ); document.write( "4x=120 \n" ); document.write( "x=30 student's age now \n" ); document.write( "plug x to get director's age \n" ); document.write( " \n" ); document.write( " |