document.write( "Question 730838: Regarding algebfra, polynomials --\r
\n" ); document.write( "\n" ); document.write( "Please help me solve this problem. I know the answer is x = 5, but I'm having trouble arriving at the answer correctly.\r
\n" ); document.write( "\n" ); document.write( "\"The area of a rectangle is 55 square feet. The height is x and the length is 2x + 1. Solve for x.\"\r
\n" ); document.write( "\n" ); document.write( "\"+x%282x+%2B+1%29+=+55+\"\r
\n" ); document.write( "\n" ); document.write( "2x^2 + x = 55\r
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\n" ); document.write( "\n" ); document.write( "2x^2 + x -55 = 0\r
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\n" ); document.write( "\n" ); document.write( "My email address is mjj1107@sbcglobal.net.\r
\n" ); document.write( "\n" ); document.write( "Thanks.\r
\n" ); document.write( "\n" ); document.write( "Mary Jane
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Algebra.Com's Answer #446974 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
You are on the right path and just need to solve \"2x%5E2+%2B+x+-55+=+0+\"
\n" ); document.write( "There are easier quadratic equations\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "I know of 3 ways to solve quadratic equations like \"2x%5E2+%2B+x+-55+=+0+\"
\n" ); document.write( "Factoring will work if the answers are rational numbers.
\n" ); document.write( "Completing the square will always work.
\n" ); document.write( "Using the quadratic formula will always work too.
\n" ); document.write( "
\n" ); document.write( "FACTORING:
\n" ); document.write( "When the leading coefficient is not 1 or -1, factoring is a little harder.
\n" ); document.write( "In this case, you must look for pairs of factors of \"2%2A55=110\" .
\n" ); document.write( "Giving a negative sign to one factor and a positive sign to the other, they must add up to the coefficient of the term in x, 1.
\n" ); document.write( "The number 110 can be written as 4 different products:
\n" ); document.write( "\"110=1%2A110\"
\n" ); document.write( "\"110=2%2A55\"
\n" ); document.write( "\"110=5%2A22\"
\n" ); document.write( "\"110=10%2A11\"
\n" ); document.write( "The last one is the one that works because \"11-10=1\"
\n" ); document.write( "So we use 11 and -10 as coefficients of x and write \"2x%5E2+%2B+x+-55\" as
\n" ); document.write( "\"2x%5E2+%2B+11x+-10x+-55\"
\n" ); document.write( "Then we factor by grouping, like this:
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\n" ); document.write( "So, since \"2x%5E2+%2B+x+-55=%282x%2B11%29%28x-5%29\" we re-write the equation as
\n" ); document.write( "\"%282x%2B11%29%28x-5%29=0\" and find the solutions that make
\n" ); document.write( "\"2x%2B11=0\" --> \"x=-11%2F2\" and
\n" ); document.write( "\"x-5=q\" --> \"x=5\"
\n" ); document.write( "Since x must be positive to be the width of a rectangle, the only solution is \"x=5%29\".
\n" ); document.write( "
\n" ); document.write( "COMPLETING THE SQUARE:
\n" ); document.write( "\"2x%5E2+%2B+x+=+55+\" --> \"x%5E2%2Bx%2F2=55%2F2\" dividing both sides by 2
\n" ); document.write( "\"x%5E2%2Bx%2F2\" is part of \"x%5E2%2Bx%2F2%2B1%2F16=%28x%2B1%2F4%29%5E2\" so if we add \"1%2F16\" to both sides we \"complete the square:
\n" ); document.write( "\"x%5E2%2Bx%2F2=55%2F2\" --> \"x%5E2%2Bx%2F2%2B1%2F16=55%2F2%2B1%2F16\" --> \"%28x%2B1%2F4%29%5E2=440%2F16%2B1%2F16\" --> \"%28x%2B1%2F4%29%5E2=441%2F16\"
\n" ); document.write( "\"441%2F16=21%5E2%2F4%5E2=%2821%2F4%29%5E2\" or \"sqrt%28441%2F16%29=sqrt%28441%29%2Fsqrt%2816%29=21%2F4\" so
\n" ); document.write( "either \"x%2B1%2F4=21%2F4\" --> \"x=21%2F4-1%2F4\" --> \"x=20%2F4\" --> \"x=5\"
\n" ); document.write( "or \"x%2B1%2F4=-21%2F4\" --> \"x=-21%2F4-1%2F4\" --> \"x=-22%2F4\" --> \"x=-11%2F2\"
\n" ); document.write( "Same solutions to the equation, and the only solution to the geometry problem is \"x=5\".
\n" ); document.write( "
\n" ); document.write( "THE QUADRATIC FORMULA
\n" ); document.write( "is a formula that derives from completing the square.
\n" ); document.write( "I never set to memorize it, but I have been using it for so long that I remember it.
\n" ); document.write( "For an equation of the form
\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\" the solutions are given by the quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "In the case of \"2x%5E2+%2B+x+-55+=+0+\" \"a=2\" , \"b=1\" and \"c=-55\" so
\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%281%5E2-4%2A2%2A%28-55%29+%29%29%2F%282%2A2%29+\"
\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%281%2B440%29%29%2F4+\"
\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28441%29%29%2F4+\"
\n" ); document.write( "\"x+=+%28-1+%2B-+21%29%2F4+\"
\n" ); document.write( "So the solutions of the equation are
\n" ); document.write( "\"x=%28-1+%2B+21%29%2F4+\" --> \"x=20%2F4\" --> \"x=5%7D%7D+and%0D%0A%7B%7B%7Bx=%28-1+-+21%29%2F4+\" --> \"x=-22%2F4\" --> \"x=-11%2F2\"
\n" ); document.write( "Since \"_11%2F2\" cannot be the with of a rectangle, the only solution is \"x=5\" .
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