document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=731025>Question 731025</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello I have this word problem and i'm really confused on how to to write the equation for it. Here's the problem(Sorry for its length): A restaurant manager bought 20 packages of bagels. Some packages contained 6 bagels each, and the rest contained 12 bagels each. There were 168 bagels in all.How many packages of 12 bagels did the manager buy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446962 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s= number of six bagel packages.  Let t=number of twelve package bagels.<P><BR>\n" );
document.write( "s + t = 20 since there are a total of 20 packages, which is the sum of the number of different types of packages.<P><BR>\n" );
document.write( "6s + 12t = 168,  Each six bagel package contributes 6 bagels for a total of 6s bagels.  Each twelve bagel package contributes 12 bagels for a total of 12t bagels.  The sum is the total number of bagels.<P><BR>\n" );
document.write( "Solve the first equation for s in terms of t.  s = 20 - t.<P><BR>\n" );
document.write( "Substitute that into the second equation, and solve for t.<P><BR>\n" );
document.write( "6(20-t) + 12t = 168<P><BR>\n" );
document.write( "120 - 6t + 12t = 168<P><BR>\n" );
document.write( "6t = 48  (And Mr. T = tough, fool).<P><BR>\n" );
document.write( "t = 8<P><BR>\n" );
document.write( "The manager bought 8 twelve bagel packages.\r<BR>\n" );
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