document.write( "Question 731016: We have 20% alcohol solution and 50% acid solution, how many pints must be added from each to obtain 8 pints of 30%?\r
\n" );
document.write( "\n" );
document.write( "-Because it mixes alcohol and acid solutions, I'm not sure if the same equation for mixtures works for this problem. \n" );
document.write( "
Algebra.Com's Answer #446956 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Bad question. No specification for the ratio of the alcohol to the acid in the 8 pints mixture, and you cannot expect to INCREASE the amount of alcohol from 20% to 30%. If you want to accept this as an open-ended question, then you could pick any ratio between the alcohol and the acid that is possible. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "One way to approach is to make a total percent concentration rational equation and give one of the conditions that the volumes of each quantity of the available solutions must sum to 8 pints. The thought is like this:\r \n" ); document.write( "\n" ); document.write( "x for the alcohol volume, y for the acid volume, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "According to that, you are back to a typical two component mixture problem without regard to the identity of the pure material in the available solutions or the resulting solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Solve for x and y. \n" ); document.write( " |