document.write( "Question 731016: We have 20% alcohol solution and 50% acid solution, how many pints must be added from each to obtain 8 pints of 30%?\r
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document.write( "-Because it mixes alcohol and acid solutions, I'm not sure if the same equation for mixtures works for this problem. \n" );
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Algebra.Com's Answer #446954 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Percent ---------------- quantity \n" ); document.write( "Solution I 20.00% ---------------- x pints \n" ); document.write( "Solution II 50.00% ------ 8 - x pints \n" ); document.write( "Mixture 30.00% ---------------- 8 \n" ); document.write( " 8 \n" ); document.write( "20.00% x + 50.00% ( 8 - x ) = 30.00% * 8 \n" ); document.write( "20 x + 50 ( 8 - x ) = 240 \n" ); document.write( "20 x + 400 - 50 x = 240 \n" ); document.write( "20 x - 50 x = 240 - -400 \n" ); document.write( "-30 x = -160 \n" ); document.write( "/ -30 \n" ); document.write( " x = 5.33 pints 20.00% Solution I \n" ); document.write( " 2.67 pints 50.00% Solution II \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |