document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=730945>Question 730945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The radiator in a certain make of car needs to contain 40 liters of 40% antifreeze. The radiator now contains 40 liters of 20% antifreeze. How many liters of this solution must be drained and replaced with 100%  antifreeze to get the desired strength?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446946 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You remove some volume, q of the 20% antifreeze.  The amount of pure antifreeze in the tank is then 40*0.20-q*0.20 mass of pure antifreeze.  Next q volume of the 100% antifreeze is added, so the amount of pure antifreeze in the tank becomes 40*0.20-q*0.20+q*1.00 mass of pure antifreeze.  \r<BR>\n" );
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document.write( "All that was done so that the volume of antifreeze solution in the tank is again 40 liters of volume.  NOW, we expect the result to be 0.40 or 40% antifreeze for that 40 liters.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2840%2A0.20-q%2A0.20%2Bq%2A1.00%29%2F40=0.40 ALIGN=MIDDLE  ALT=\"%2840%2A0.20-q%2A0.20%2Bq%2A1.00%29%2F40=0.40\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and you need to solve for q. </SPAN>\n" );
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