document.write( "Question 730820: A grab bag contains 10 $1 prizes, 6 $5 prizes, and 5 $20 prizes. Three prizes are chosen at random. Find the probability that exactly 2 $20 prizes are chosen? I get that I needed to figure 21C3=1330 (Total # of ways to choose 3 prizes), and that number will need to be divided into the number of ways you can pick so two are $20 prizes, but I can't figure out how to get the number of ways you can pick so two are $20 prizes? I can't get that numerator. Please help, I'm having this problem on all my homework, stuck in the same spot, and the homework help button skips over this part. Thanks! \n" ); document.write( "

Algebra.Com's Answer #446869 by stanbon(75887) $\"\"$ $\"About$

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A grab bag contains 10 $1 prizes, 6 $5 prizes, and 5 $20 prizes. Three prizes are chosen at random. Find the probability that exactly 2 $20 prizes are chosen?
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\n" ); document.write( "There are 21 prizes.
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\n" ); document.write( "# of ways to succeed: 5C2*11C1 = 10*11 = 110
\n" ); document.write( "# of possible outcomes: 21C3 = 1330
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\n" ); document.write( "Probability of selecting 2 $20 prizes when choosing 3: 110/1330 = 11/133
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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