document.write( "Question 730724: a father is ten times his daughter AGe now. in 5 years time he will be 5 times as old as his daughter. How old are each of them now? \n" ); document.write( "
Algebra.Com's Answer #446858 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a father is ten times his daughter AGe now. \n" ); document.write( "f = 10d \n" ); document.write( " in 5 years time he will be 5 times as old as his daughter. \n" ); document.write( "f + 5 = 5(d+5) \n" ); document.write( "f + 5 = 5d + 25 \n" ); document.write( "f = 5d + 25 - 5 \n" ); document.write( "f = 5d + 20 \n" ); document.write( ": \n" ); document.write( " How old are each of them now? \n" ); document.write( "replace f with 10d \n" ); document.write( "10d = 5d + 20 \n" ); document.write( "10d - 5d = 20 \n" ); document.write( "5d = 20 \n" ); document.write( "d = 20/5 \n" ); document.write( "d = 4 yrs old is the daughter now \n" ); document.write( "I'll let you find Dad's age \n" ); document.write( " |