document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=730733>Question 730733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a farmer did head count and got 200 livestock (and he keeps chicken n pigs), counted the legs and got 540, how many chicken were there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446807 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> C is chickens and P is pigs.  Each animal has one head so C + P = 200.<P><BR>\n" );
document.write( "Chickens have two legs, so for legs chickens add 2*C  (2 times the number of chickens.)  Pigs have four legs, so for legs pigs add 4*P.  2C + 4P = 540.<P><BR>\n" );
document.write( "From the first equation solve for C:  C = 200-P.  Substitute that into the second equation.<P><BR>\n" );
document.write( "2(200-P)+4P = 540<P><BR>\n" );
document.write( "400 -2P + 4P = 540<P><BR>\n" );
document.write( "2P = 140<P><BR>\n" );
document.write( "P = 70.<P><BR>\n" );
document.write( "C = 200-70=130.<BR>\n" );
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