document.write( "Question 730693: In a diagram of a rectangle the lenght on the top is 1(x+9)/3 and the lenght below is x-1/2.The width is x/4.
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document.write( "Could you help me find the value of 'x' and also the lenght and the width.
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document.write( "Thanks. \n" );
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Algebra.Com's Answer #446799 by stanbon(75887) ![]() You can put this solution on YOUR website! In a diagram of a rectangle the length on the top is 1(x+9)/3 and the length below is x-1/2. The width is x/4. \n" ); document.write( "Could you help me find the value of 'x' and also the length and the width. \n" ); document.write( "----- \n" ); document.write( "If the length on the top and the length on the bottom \n" ); document.write( "are as you have indicated, \n" ); document.write( "(1(x+9)/3 = (x-(1/2) \n" ); document.write( "--- \n" ); document.write( "x+9 = 3x-(3/2) \n" ); document.write( "2x = 10.5 \n" ); document.write( "x = 5.25 \n" ); document.write( "--- \n" ); document.write( "Then the length is x-1/2 = 5.25-(1/2) = 4.75 \n" ); document.write( "and the width is x/4 = 5.25/4 = 1.3125 \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |