document.write( "Question 730616: Find an equation for the line that passes through (0,-5) and is perpendicular to the graph of x+3y=4. Write in Slope-Intercept form:\r
\n" ); document.write( "\n" ); document.write( "So far I have\r
\n" ); document.write( "\n" ); document.write( "x+3y-3y-4=4-3y-4
\n" ); document.write( "x-4=-3y
\n" ); document.write( "then divide each side by -3
\n" ); document.write( "-1x/3-(-4/3)=y or y=-1x/3+3/4\r
\n" ); document.write( "\n" ); document.write( "-5=-1(0)/3+3/4 it gets mixed up from here, am I even doing this correctly? Thanks
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Algebra.Com's Answer #446758 by Alan3354(69443) $\"\"$ $\"About$

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Find an equation for the line that passes through (0,-5) and is perpendicular to the graph of x+3y=4. Write in Slope-Intercept form:
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\n" ); document.write( "Find the slope of the line.
\n" ); document.write( "x+3y=4
\n" ); document.write( "Solve for y\r
\n" ); document.write( "\n" ); document.write( "y = (-1/3)x + 4/3
\n" ); document.write( "The slope = -1/3
\n" ); document.write( "The slope of lines perpendicular is the negative inverse = 3
\n" ); document.write( "-----------
\n" ); document.write( "(0,-5) is b, the y-intercept
\n" ); document.write( "--> y = 3x - 5
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