document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=730624>Question 730624</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man is ten times as old as his daughter, in 5 years time he will be 5 times as old  as his daughter. how old are each of them now ? <BR>\n" );
document.write( "Please send breakdown of solution \r<BR>\n" );
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document.write( "a father is 48 years old and his son 14 years old ,in how many years will the father be three times older than the son?<BR>\n" );
document.write( "Please send break down and solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446756 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446756\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> daughter 's age =x<BR>\n" );
document.write( "father's age = 10x\r<BR>\n" );
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document.write( "5 years later<BR>\n" );
document.write( "daughter's age = x+5<BR>\n" );
document.write( "father's age = 10x+5\r<BR>\n" );
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document.write( "10x+5 = 5(x+5)\r<BR>\n" );
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document.write( "10x+5=5x+25<BR>\n" );
document.write( "10x-5x=25-5<BR>\n" );
document.write( "5x=20<BR>\n" );
document.write( "x=4\r<BR>\n" );
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document.write( "daughter 4 years<BR>\n" );
document.write( "Father 40 years </SPAN>\n" );
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