document.write( "Question 730609: A certain automobile cooling system contains 11.0 liters of of coolant that is 15% antifreeze. How many liters of mixture must be removed so that, when it is replaced with pure antifreeze, a mixture of 25% antifreeze will result?\r
\n" ); document.write( "\n" ); document.write( "I know that I have to use the 100% somewhere, but I can't see how to use it. It's very odd seeing this as a subtraction problem.\r
\n" ); document.write( "\n" ); document.write( "I tried
\n" ); document.write( " 15% 11-x .15
\n" ); document.write( " 100% x 1
\n" ); document.write( " 25% 11 .25
\n" ); document.write( "I need to see it in a table form so that my mind can process it.
\n" ); document.write( "thanks Mark
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Algebra.Com's Answer #446752 by lwsshak3(11628)\"\" \"About 
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A certain automobile cooling system contains 11.0 liters of of coolant that is 15% antifreeze. How many liters of mixture must be removed so that, when it is replaced with pure antifreeze, a mixture of 25% antifreeze will result?
\n" ); document.write( "***
\n" ); document.write( "let x=amt of 15% antifreeze to be removed and replaced with pure antifreeze
\n" ); document.write( "11-x=amt of 15% antifreeze remaining
\n" ); document.write( "..
\n" ); document.write( "15%(11-x)+100%x=25%*11
\n" ); document.write( "1.65-.15x+x=2.75
\n" ); document.write( ".85x=1.1
\n" ); document.write( "x≈1.294
\n" ); document.write( "amt of 15% antifreeze to be removed and replaced with pure antifreeze≈1.294 liters
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