document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=730555>Question 730555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Train leaves Boston at 2:00pm. A second train leaves the same city in the same direction at 8:00pm. The second train travels 150mph faster than the first. If the second overtakes the first at 10pm, what is the speed of each of the two trains.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446729 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446729\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Speed of first train ---------------x<BR>\n" );
document.write( "speed of train II-----------------x+150\r<BR>\n" );
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document.write( "Second train leaves after 6 hours\r<BR>\n" );
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document.write( "the first train has traveled 6x miles before train II starts\r<BR>\n" );
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document.write( "catch up speed = 150\r<BR>\n" );
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document.write( "catch up distance = 6x\r<BR>\n" );
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document.write( "catch up time =8 hours\r<BR>\n" );
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document.write( "8=6x/150<BR>\n" );
document.write( "x=200  mph speed of first train<BR>\n" );
document.write( "200+150 = 350 mph is the speed of train II </SPAN>\n" );
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