document.write( "Question 730511: which conic section is 3(x+5)^2+3y-15=0 \n" ); document.write( "

Algebra.Com's Answer #446714 by lwsshak3(11628) $\"\"$ $\"About$

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which conic section is
\n" ); document.write( "3(x+5)^2+3y-15=0
\n" ); document.write( "3(x^2+10x+25)+3y-15=0
\n" ); document.write( "3x^2+30x+75+3y-15=0
\n" ); document.write( "3x^2+30x+3y=-60
\n" ); document.write( "x^2+10x+y=-20
\n" ); document.write( "complete the square:
\n" ); document.write( "(x^2+10x+25)+y=-20+25
\n" ); document.write( "(x+5)^2+y=5
\n" ); document.write( "y=-(x+5)^2+5
\n" ); document.write( "This is a parabola that opens down with vertex at (-5,5) \n" ); document.write( "

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