document.write( "Question 730328: If two cars start from 92 miles apart and travel directly towards each other, and one car starts at 11Am and the other starts at 11:15AM and goes 6 miles per hour faster, and they meet up at noon, what is the average speed of each car? \n" ); document.write( "
Algebra.Com's Answer #446713 by ankor@dixie-net.com(22740)\"\" \"About 
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If two cars start from 92 miles apart and travel directly towards each other,
\n" ); document.write( " and one car starts at 11Am and the other starts at 11:15AM and goes 6 miles
\n" ); document.write( " per hour faster, and they meet up at noon, what is the average speed of each car?
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\n" ); document.write( "Let s = speed of the Car1
\n" ); document.write( "then
\n" ); document.write( "(s+6) = speed of Car2
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\n" ); document.write( "The travel time of each car from the information given
\n" ); document.write( "Car 1: 1 hr, Car 2: 45 min or .75 hr
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\n" ); document.write( "Write a distance equation: dist = time * speed
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\n" ); document.write( "Car 1 dist + Car 2 dist = 92 mi
\n" ); document.write( "1s + .75(s+6) = 92
\n" ); document.write( "s + .75s + 4.5 = 92
\n" ); document.write( "1.75s = 92 - 4.5
\n" ); document.write( "s = \"87.5%2F1.75\"
\n" ); document.write( "s = 50 mph is the speed of Car 1
\n" ); document.write( "then, obviously
\n" ); document.write( "56 mph is the speed of car 2
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\n" ); document.write( "Check this by finding the actual distance each car went
\n" ); document.write( "1*50 = 50 mi
\n" ); document.write( ".75*56 = 42 mi
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\n" ); document.write( "total dist: 92 mi
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