document.write( "Question 730328: If two cars start from 92 miles apart and travel directly towards each other, and one car starts at 11Am and the other starts at 11:15AM and goes 6 miles per hour faster, and they meet up at noon, what is the average speed of each car? \n" ); document.write( "
Algebra.Com's Answer #446713 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If two cars start from 92 miles apart and travel directly towards each other, \n" ); document.write( " and one car starts at 11Am and the other starts at 11:15AM and goes 6 miles \n" ); document.write( " per hour faster, and they meet up at noon, what is the average speed of each car? \n" ); document.write( ": \n" ); document.write( "Let s = speed of the Car1 \n" ); document.write( "then \n" ); document.write( "(s+6) = speed of Car2 \n" ); document.write( "; \n" ); document.write( "The travel time of each car from the information given \n" ); document.write( "Car 1: 1 hr, Car 2: 45 min or .75 hr \n" ); document.write( ": \n" ); document.write( "Write a distance equation: dist = time * speed \n" ); document.write( ": \n" ); document.write( "Car 1 dist + Car 2 dist = 92 mi \n" ); document.write( "1s + .75(s+6) = 92 \n" ); document.write( "s + .75s + 4.5 = 92 \n" ); document.write( "1.75s = 92 - 4.5 \n" ); document.write( "s = \n" ); document.write( "s = 50 mph is the speed of Car 1 \n" ); document.write( "then, obviously \n" ); document.write( "56 mph is the speed of car 2 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the actual distance each car went \n" ); document.write( "1*50 = 50 mi \n" ); document.write( ".75*56 = 42 mi \n" ); document.write( "---------------- \n" ); document.write( "total dist: 92 mi \n" ); document.write( " |