document.write( "Question 730436: IF 1000 YEARS EQUAL A 24 HOUR DAY HOW MUCH WOULD 1 SECOND EQUAL PLESE HELP ME \n" ); document.write( "
Algebra.Com's Answer #446683 by MathLover1(20855)\"\" \"About 
You can put this solution on YOUR website!
\"1+day+=+24+hours+=+1440min=86400sec\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so, in \"1sec\" you will have \"1000%2F86400=0.011574074074074074074074074074074years\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "But if you want to find out an exact number you must do some research, I might be wrong here, but a year with 1 extra day occurs once every 4th year, so:\r
\n" ); document.write( "\n" ); document.write( "1000/4 = 250 this is 250 years with 1 extra day, which changes the math into making us take into account that 250 years of those 1000 has 366 days instead of 365\r
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Or, you can forget leap years and use a more sane representation of years such Julian years (\"365.25\" days, exactly) or tropical years (\"365.24218967\" days at the epoch J2000.0) \r
\n" ); document.write( "\n" ); document.write( "\"365.25%2A24=8766h=31557600sec\"\r
\n" ); document.write( "\n" ); document.write( "so in \"1000\" years will be \"365.25%2A1000=+365250\" days\r
\n" ); document.write( "\n" ); document.write( "\"365250+%2F31557600=0.011574074074074074074074074074074\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );