document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64026>Question 64026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by factoring<BR>\n" );
document.write( "x^2-10x=-16 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44664 by </B><A HREF=/tutors/aboutme.mpl?userid=praseenakos@yahoo.com><B>praseenakos@yahoo.com(507)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=praseenakos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=praseenakos@yahoo.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> QUESTION:\r<BR>\n" );
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document.write( "solve by factoring<BR>\n" );
document.write( "x^2-10x=-16\r<BR>\n" );
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document.write( "ANSWER:\r<BR>\n" );
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document.write( "x^2-10x=-16\r<BR>\n" );
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document.write( "Add  +16 on both sides of the equation \r<BR>\n" );
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document.write( "==> x^2-10x + 1`6= -16 + 16\r<BR>\n" );
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document.write( "==> x^2-10x + 16 = 0\r<BR>\n" );
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document.write( "This is a quadratic equation.\r<BR>\n" );
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document.write( "We can use quadratic fromula as well as factorisation method.\r<BR>\n" );
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document.write( "Factorisation method==>\r<BR>\n" );
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document.write( " x^2-10x + 16 = 0\r<BR>\n" );
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document.write( "First of all split the middle term.\r<BR>\n" );
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document.write( "For that find out two numbers whose sum is  - 10 ( coefficient of x ) and whose product is  +16  ( constant term )\r<BR>\n" );
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document.write( "Such two numbers are  -8 and -2(( To get these numbers consider the factors of +16 , constant terms and try with different sign untill you get the numbers.)\r<BR>\n" );
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document.write( "Because,\r<BR>\n" );
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document.write( " -8 * -2 =  -16    and  -8 + ( -2 ) = -10\r<BR>\n" );
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document.write( "Now rewrite the given equation as follows,\r<BR>\n" );
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document.write( " x^2 - 8x - 2x + 16 = 0\r<BR>\n" );
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document.write( "Now group the terms as follows,\r<BR>\n" );
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document.write( "  (x^2 - 8x ) -  (2x -  16 ) = 0  ( when we  put negative sign before the brackets, the sign inside the brackets will change)\r<BR>\n" );
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document.write( "Now take out common factor from each brackets.\r<BR>\n" );
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document.write( "==> x ( x - 8 ) - 2 ( x - 8 ) = 0\r<BR>\n" );
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document.write( "Again ( x - 8 ) is common in both terms, take it out.\r<BR>\n" );
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document.write( "==> ( x - 8 ) ( x - 2 ) = 0\r<BR>\n" );
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document.write( "Here we can take,\r<BR>\n" );
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document.write( "either  ( x - 8 ) = 0  or  ( x - 2 )= 0 \r<BR>\n" );
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document.write( "If ( x - 8 ) = 0 ===> x = 8 and\r<BR>\n" );
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document.write( "If ( x - 2 ) = 0 ===>  x = 2\r<BR>\n" );
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document.write( "So solution of given equation is,\r<BR>\n" );
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document.write( "x = 2  and\r<BR>\n" );
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document.write( "x = 8.\r<BR>\n" );
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document.write( "Hope you understood.\r<BR>\n" );
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document.write( "Regards.\r<BR>\n" );
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document.write( "praseenakos@yahoo.co.in\r<BR>\n" );
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document.write( " </SPAN>\n" );
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