document.write( "Question 64016This question is from textbook
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Algebra.Com's Answer #44662 by Edwin McCravy(20055)\"\" \"About 
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SOLVE BY COMPLETING THE SQUARE:\r\n" );
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document.write( "2X - 24 = -2X²\r\n" );
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document.write( "First get all terms containing X on the left side\r\n" );
document.write( "and the number term on the right. Make sure the term\r\n" );
document.write( "containing X² comes first on the left:\r\n" );
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document.write( "2X² + 2X = 24\r\n" );
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document.write( "Divide through by the coefficient of X², which is 2:\r\n" );
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document.write( "2X²/2 + 2X/2 = 24/2\r\n" );
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document.write( "      X² + X = 12\r\n" );
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document.write( "Multiply the coefficient of X, which is 1 by 1/2.\r\n" );
document.write( "This gives 1/2.  Now square this result, which\r\n" );
document.write( "gives 1/4.  Now add +1/4 to both sides of the equation:\r\n" );
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document.write( "X² + X + 1/4 = 12 + 1/4\r\n" );
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document.write( "Factor the left side as (X + 1/2)(X + 1/2) or (X + 1/2)²\r\n" );
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document.write( "(X + 1/2)² = 12 + 1/4\r\n" );
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document.write( "Combine the terms on the right:\r\n" );
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document.write( "(X + 1/2)² = 49/4\r\n" );
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document.write( "Take the square roots of both sides:\r\n" );
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document.write( " X + 1/2 = ±Ö49/4\r\n" );
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document.write( " X + 1/2 = ±7/2\r\n" );
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document.write( "Add -1/2 to both sides:\r\n" );
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document.write( "       X = -1/2 ± 7/2\r\n" );
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document.write( "Using the +\r\n" );
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document.write( "       X = -1/2 + 7/2 = 6/2 = 3\r\n" );
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document.write( "Using the -\r\n" );
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document.write( "       X = -1/2 - 7/2 = -8/2 = -4\r\n" );
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document.write( "Edwin

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