document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=730190>Question 730190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> system of equations<BR>\n" );
document.write( "2 cars start from points 92 miles apart and travel directly towards each other. one car starts at 11am and travels slower and the other starts at 11:15am and goes faster to make up for lost time. they meet at 12pm find the average speed of each car, if the slower car travels 6 mph slower than the faster one. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446546 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the speed of slower car be x <BR>\n" );
document.write( "the speed of car II = x+6\r<BR>\n" );
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document.write( "They meet after 1 hour after car I starts\r<BR>\n" );
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document.write( "distance by car I = x<BR>\n" );
document.write( "distance by car II = (x+6)*3/4........... ( speed * time)\r<BR>\n" );
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document.write( "x+3/4(x+6)=92\r<BR>\n" );
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document.write( "multiply by 4<BR>\n" );
document.write( "4x+3(x+6)=368\r<BR>\n" );
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document.write( "4x+3x+18=350<BR>\n" );
document.write( "7x=350<BR>\n" );
document.write( "x=50 \r<BR>\n" );
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document.write( "50 & 56mph </SPAN>\n" );
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