document.write( "Question 729924: Solve in [0,2pi)
\n" ); document.write( "sec(2theta)tan(theta)-sec(2theta)-2tan(theta)+2=0\r
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\n" ); document.write( "\n" ); document.write( "Please help!
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Algebra.Com's Answer #446541 by lwsshak3(11628)\"\" \"About 
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Solve in [0,2pi)
\n" ); document.write( "sec(2theta)tan(theta)-sec(2theta)-2tan(theta)+2=0
\n" ); document.write( "sec2xtanx-sec2x-2tanx+2=0
\n" ); document.write( "sec2x(tanx-1)-2(tanx-1)=0
\n" ); document.write( "(tanx-1)(sec2x-2)=0
\n" ); document.write( "..
\n" ); document.write( "tanx-1=0
\n" ); document.write( "tanx=1
\n" ); document.write( "x=π/4, 5π/4 (in quadrants I and III where tan>0)
\n" ); document.write( "..
\n" ); document.write( "(sec2x-2)=0
\n" ); document.write( "sec2x=2
\n" ); document.write( "cos2x=1/2
\n" ); document.write( "2x=π/3, 5π/3 (in quadrants I and IV where cos>0)
\n" ); document.write( "x=π/6, 5π/6
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