document.write( "Question 730189: To determine if a function is odd even or neither.
\n" ); document.write( "f(x) = x^3 - x^2. Ok substitute (-x)^3 - (-x)^2\r
\n" ); document.write( "\n" ); document.write( "-x^3 + x^2. How can I determine if it is odd even or neither. to me it is mixed the x^3 becomes, -x^3 and x^2 becomes -x^2
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Algebra.Com's Answer #446539 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
It's neither because there's a mix of odd and even exponents.\r
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\n" ); document.write( "\n" ); document.write( "If it was even, then you'd have all even exponents.\r
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\n" ); document.write( "\n" ); document.write( "If it was odd, then you'd have all odd exponents.\r
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\n" ); document.write( "\n" ); document.write( "This trick only works for polynomials.\r
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\n" ); document.write( "\n" ); document.write( "f(x) = x^3 - x^2\r
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\n" ); document.write( "\n" ); document.write( "f(-x) = (-x)^3 - (-x)^2\r
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\n" ); document.write( "\n" ); document.write( "f(-x) = -x^3 - x^2\r
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\n" ); document.write( "\n" ); document.write( "So f(x) does NOT equal f(-x) which means that f(x) is NOT even.\r
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\n" ); document.write( "\n" ); document.write( "f(x) = x^3 - x^2\r
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\n" ); document.write( "\n" ); document.write( "-f(x) = -(x^3 - x^2)\r
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\n" ); document.write( "\n" ); document.write( "-f(x) = -x^3 + x^2\r
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\n" ); document.write( "\n" ); document.write( "-f(x) = -x^3 + x^2\r
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\n" ); document.write( "\n" ); document.write( "So f(-x) does NOT equal -f(x) which means that f(x) is NOT odd.\r
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\n" ); document.write( "\n" ); document.write( "Final answer: f(x) is neither even nor odd.
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