document.write( "Question 730161: A ball is thrown upward from the top of a building. The ball's height above the ground after T seconds is given by the function: h(t) = -16t^2+48t+32.
\n" ); document.write( "A. What is the initial height (i.e. the height of the building)?
\n" ); document.write( "B. How high did the ball go?
\n" ); document.write( "C. When does the ball hit the ground?
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Algebra.Com's Answer #446516 by nerdybill(7384)\"\" \"About 
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A ball is thrown upward from the top of a building. The ball's height above the ground after T seconds is given by the function: h(t) = -16t^2+48t+32.
\n" ); document.write( "A. What is the initial height (i.e. the height of the building)?
\n" ); document.write( "initial height is when t=0:
\n" ); document.write( "h(t) = -16t^2+48t+32
\n" ); document.write( "h(0) = -16(0)^2+48(0)+32
\n" ); document.write( "h(0) = 32 feet
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\n" ); document.write( "B. How high did the ball go?
\n" ); document.write( "vertex is at max:
\n" ); document.write( "time, at vertex:
\n" ); document.write( "t = -b/(2a)
\n" ); document.write( "t = -48/(2(-16))
\n" ); document.write( "t = -48/(-32)
\n" ); document.write( "t = 3/2
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\n" ); document.write( "Height at t=3/2:
\n" ); document.write( "h(3/2) = -16(3/2)^2+48(3/2)+32
\n" ); document.write( "h(3/2) = -16(9/4)+24(3)+32
\n" ); document.write( "h(3/2) = -4(9)+24(3)+32
\n" ); document.write( "h(3/2) = -36+72+32
\n" ); document.write( "h(3/2) = 68 feet
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\n" ); document.write( "C. When does the ball hit the ground?
\n" ); document.write( "set h(t) to zero and solve for t:
\n" ); document.write( "h(t) = -16t^2+48t+32
\n" ); document.write( "0 = -16t^2+48t+32
\n" ); document.write( "0 = t^2-3t-2
\n" ); document.write( "solve by applying the \"quadratic formula\" to get:
\n" ); document.write( "t = {3.56, -0.56}
\n" ); document.write( "throw out the negative solution (extraneous) leaving
\n" ); document.write( "t = 3.56 seconds
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\n" ); document.write( "Details of quadratic formula follows:
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-3x%2B-2+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-3%29%5E2-4%2A1%2A-2=17\".
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\n" ); document.write( " Discriminant d=17 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--3%2B-sqrt%28+17+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-3%29%2Bsqrt%28+17+%29%29%2F2%5C1+=+3.56155281280883\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-3%29-sqrt%28+17+%29%29%2F2%5C1+=+-0.56155281280883\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-3x%2B-2\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-3x%2B-2+=+1%28x-3.56155281280883%29%2A%28x--0.56155281280883%29\"
\n" ); document.write( " Again, the answer is: 3.56155281280883, -0.56155281280883.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-3%2Ax%2B-2+%29\"
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