document.write( "Question 730123: An investor invested a total of $2,500.00 in two mutual funds. one fund earned 9% of the profit while the other earned a 6% profit. If the investors total profit was $165.00 how much was invested in each mutual fund? \n" ); document.write( "
Algebra.Com's Answer #446495 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 9.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 6.00% per annum ------------ Amount invested = y \n" ); document.write( " 2500 \n" ); document.write( "Interest----- 165.00 \n" ); document.write( " \n" ); document.write( "Part I 9.00% per annum ---x * \n" ); document.write( "Part II 6.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 2500 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "9.00% x + 6.00% y= 165 \n" ); document.write( "Multiply by 100 \n" ); document.write( "9 x + 6 y= 16500.00 --------2 \n" ); document.write( "Multiply (1) by -9 \n" ); document.write( "we get \n" ); document.write( "-9 x -9 y= -22500.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -3 y= -6000 \n" ); document.write( "divide by -3 \n" ); document.write( " y = 2000 - x) \n" ); document.write( "Part I 9.00% $ 500 \n" ); document.write( "Part II 6.00% $ 2000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "500 --------- 9.00% ------- 45.00 \n" ); document.write( "2000 ------------- 6.00% ------- 120.00 \n" ); document.write( "Total -------------------- 165.00 \n" ); document.write( " 11.6 \n" ); document.write( "m.ananth@hotmail.ca 1520 \n" ); document.write( " \n" ); document.write( " |