document.write( "Question 730119: Can someone help me with this please???\r
\n" ); document.write( "\n" ); document.write( "Write the slope intercept form of the line that pass through point A(-5,9) and is perpendicular to the line with equation 2y-3x+5=0
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Algebra.Com's Answer #446478 by Alan3354(69443)\"\" \"About 
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Write the slope intercept form of the line that pass through point A(-5,9) and is perpendicular to the line with equation 2y-3x+5=0
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\n" ); document.write( "Find the slope of the line, m1
\n" ); document.write( "2y-3x+5=0
\n" ); document.write( "Put it into slope-intercept form (solve for y)
\n" ); document.write( "y = (3/2)x - 5/2
\n" ); document.write( "m1 = 3/2
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\n" ); document.write( "The slope of lines perpendicular is the negative inverse = -2/3
\n" ); document.write( "m = -2/3
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\n" ); document.write( "Use y = mx + b and the point to find b, the y-intercept
\n" ); document.write( "9 = (-2/3)*-5 + b
\n" ); document.write( "b = 17/3
\n" ); document.write( "--> y = (-2/3)x + 17/3 is the equation
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