document.write( "Question 730068: The president of a large university wishes to estimate the average age of the students presently enrolled. From past studies, the standard deviation σ is known to be 2 years. A sample of 50 students is selected and the mean is found to be 23.3 years.
\n" ); document.write( " a. Find the 99% confidence interval of the population.
\n" ); document.write( " b. Find the 99% confidence interval for the population standard deviation
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #446451 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first part to get you started\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "a)\r
\n" ); document.write( "\n" ); document.write( "I'm assuming you want the 99% confidence interval of the population mean. Let me know if it's some other variable.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The sample mean is 23.3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The margin of error is\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "E = z*sigma/sqrt(n)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "E = 2.576*sigma/sqrt(n) ... use a calculator to find the critical value for z (let me know if you need me to show you how to do this on a calculator)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "E = 2.576*2/sqrt(50) ... plug in the other given values\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "E = 0.72860282733461\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---------------------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The lower bound of the confidence interval is \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "L = xbar - E\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "L = 23.3 - 0.72860282733461\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "L = 22.5713971726653\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The upper bound of the confidence interval is \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "L = xbar + E\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "L = 23.3 + 0.72860282733461\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "L = 24.0286028273347\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the 99% confidence interval for the population mean is \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(L, U) = (22.5713971726653, 24.0286028273347)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );