document.write( "Question 730068: The president of a large university wishes to estimate the average age of the students presently enrolled. From past studies, the standard deviation σ is known to be 2 years. A sample of 50 students is selected and the mean is found to be 23.3 years.
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document.write( " a. Find the 99% confidence interval of the population.
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document.write( " b. Find the 99% confidence interval for the population standard deviation
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Algebra.Com's Answer #446451 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! I'll do the first part to get you started\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a)\r \n" ); document.write( "\n" ); document.write( "I'm assuming you want the 99% confidence interval of the population mean. Let me know if it's some other variable.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sample mean is 23.3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The margin of error is\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "E = z*sigma/sqrt(n)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "E = 2.576*sigma/sqrt(n) ... use a calculator to find the critical value for z (let me know if you need me to show you how to do this on a calculator)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "E = 2.576*2/sqrt(50) ... plug in the other given values\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "E = 0.72860282733461\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The lower bound of the confidence interval is \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = xbar - E\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = 23.3 - 0.72860282733461\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = 22.5713971726653\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The upper bound of the confidence interval is \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = xbar + E\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = 23.3 + 0.72860282733461\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = 24.0286028273347\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the 99% confidence interval for the population mean is \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(L, U) = (22.5713971726653, 24.0286028273347)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |