document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=730020>Question 730020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> explain how you can use the length of the shorter leg of a 30,60,90 degrees triangle to find the lengths of the other two sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446445 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> explain how you can use the length of the shorter leg of a 30,60,90 degrees triangle to find the lengths of the other two sides?<BR>\n" );
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document.write( "sin(30) = 1/2 so the hypotenuse = 2 times the shorter leg<BR>\n" );
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document.write( "Then you can use Pythagoras (or sin(60)) to find the 3rd side<BR>\n" );
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