document.write( "Question 730051: Please HELP me solve this quesion !!!\r
\n" ); document.write( "\n" ); document.write( "A line passes through the points (2,9) and (9,2) ~\r
\n" ); document.write( "\n" ); document.write( "a. Write the equation of the line.\r
\n" ); document.write( "\n" ); document.write( "b. Write the equation of the parallel line going through the origin.\r
\n" ); document.write( "\n" ); document.write( "c. Write the equation of the perpendicular line through (2,9).
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Algebra.Com's Answer #446427 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "a.\r
\n" ); document.write( "\n" ); document.write( "the equation of the line passes through the points (\"2\",\"9\") and (\"9\",\"2\")\r
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Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (2, 9) and (x2, y2) = (9, 2).
\n" ); document.write( " Slope a is \"a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%282-9%29%2F%289-2%29+=+-1\".
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"-1%2A2+%2Bb+=+11\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=9--1%2A2+=+11\".
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\n" ); document.write( " y=(-1)x + (11)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "b.\r
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\n" ); document.write( "\n" ); document.write( "the equation of the parallel to line \"y=-1x%2B11\" going through the origin (\"0\",\"0\")\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"-1\" (its from the slope of \"y=-1%2Ax%2B11\" which is also \"-1\").\n" ); document.write( "Also since the unknown line goes through (0,0), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-0=-1%2A%28x-0%29\" Plug in \"m=-1\", \"x%5B1%5D=0\", and \"y%5B1%5D=0\"
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\n" ); document.write( " \"y-0=-1%2Ax%2B%281%29%280%29\" Distribute \"-1\"
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\n" ); document.write( " \"y-0=-1%2Ax-0\" Multiply
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\n" ); document.write( " \"y=-1%2Ax-0%2B0\"Add \"0\" to both sides to isolate y
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\n" ); document.write( " \"y=-1%2Ax%2B0\" Combine like terms
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\n" ); document.write( " So the equation of the line that is parallel to \"y=-1%2Ax%2B11\" and goes through (\"0\",\"0\") is \"y=-1%2Ax%2B0\"
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\n" ); document.write( " So here are the graphs of the equations \"y=-1%2Ax%2B11\" and \"y=-1%2Ax%2B0\"
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\n" ); document.write( " graph of the given equation \"y=-1%2Ax%2B11\" (red) and graph of the line \"y=-1%2Ax%2B0\"(green) that is parallel to the given graph and goes through (\"0\",\"0\")
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\n" ); document.write( "\n" ); document.write( "c.\r
\n" ); document.write( "\n" ); document.write( "the equation of the perpendicular to line \"y=-1x%2B11\" through (\"2\",\"9\")\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"-1\", you can find the perpendicular slope by this formula:
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\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=-1%2F%28-1%2F1%29\" So plug in the given slope to find the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%281%2F-1%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
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\n" ); document.write( " \"m%5Bp%5D=1%2F1\" Multiply the fractions.
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\n" ); document.write( " So the perpendicular slope is \"1\"
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\n" ); document.write( " So now we know the slope of the unknown line is \"1\" (its the negative reciprocal of \"-1\" from the line \"y=-1%2Ax%2B11\").\n" ); document.write( "Also since the unknown line goes through (2,9), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-9=1%2A%28x-2%29\" Plug in \"m=1\", \"x%5B1%5D=2\", and \"y%5B1%5D=9\"
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\n" ); document.write( " \"y-9=1%2Ax-%281%29%282%29\" Distribute \"1\"
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\n" ); document.write( " \"y-9=1%2Ax-2\" Multiply
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\n" ); document.write( " \"y=1%2Ax-2%2B9\"Add \"9\" to both sides to isolate y
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\n" ); document.write( " \"y=1%2Ax%2B7\" Combine like terms
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\n" ); document.write( " So the equation of the line that is perpendicular to \"y=-1%2Ax%2B11\" and goes through (\"2\",\"9\") is \"y=1%2Ax%2B7\"
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\n" ); document.write( " So here are the graphs of the equations \"y=-1%2Ax%2B11\" and \"y=1%2Ax%2B7\"
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\n" ); document.write( " graph of the given equation \"y=-1%2Ax%2B11\" (red) and graph of the line \"y=1%2Ax%2B7\"(green) that is perpendicular to the given graph and goes through (\"2\",\"9\")
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\n" ); document.write( "\n" ); document.write( "\"y=-1x%2B11\"...given line
\n" ); document.write( "\"y=-1x\"...parallel line
\n" ); document.write( " \"y=x%2B7\"...perpendicular\r
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\n" ); document.write( "\n" ); document.write( "let's graph them all together:\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-15%2C+15%2C+-15%2C+15%2C+-1x%2B11%2C-1x%2Cx%2B7%29+\" \r
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