document.write( "Question 729991: Im getting stuck on this system of equation by subtitution:\r
\n" ); document.write( "\n" ); document.write( "Exercise xy=-12
\n" ); document.write( " x-2y+14=0
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Algebra.Com's Answer #446328 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
System:
\n" ); document.write( " xy=-12
\n" ); document.write( " x-2y+14=0\r
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\n" ); document.write( "\n" ); document.write( "No need to be stuck. More than one way to go.\r
\n" ); document.write( "\n" ); document.write( "\"xy=-12\", gives you \"y=-12%2Fx\". Substitute into other equation.
\n" ); document.write( "\"x-2%28-12%2Fx%29%2B14=0\"
\n" ); document.write( "\"x%2B24%2Fx%2B14=0\"
\n" ); document.write( "\"x%5E2%2B24%2B14x=0\"
\n" ); document.write( "\"x%5E2%2B14x%2B24=0\" and solve for x from this.
\n" ); document.write( "...\r
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\n" ); document.write( "\n" ); document.write( "Watch for a possible extraneous value for x, although most likely not important since this is not really an application problem.
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