document.write( "Question 729947: jacob is twice as old as sue.the sum of their ages is 69 years.how old is jacob? \n" ); document.write( "
Algebra.Com's Answer #446298 by Leaf W.(135)![]() ![]() You can put this solution on YOUR website! Sue's age = x \n" ); document.write( "Jacob's age = 2*(Sue's age) = 2x \n" ); document.write( ". \n" ); document.write( "Jacob's age + Sue's age = 69 \n" ); document.write( "2x + x = 69 \n" ); document.write( "3x = 69 \n" ); document.write( "x = 23 \n" ); document.write( ". \n" ); document.write( "Sue's age (x) is 23 years old. Since Jacob's age is twice this, it is 2*23 = 46 years old. Therefore, Jacob is 46 years old. \n" ); document.write( " |