document.write( "Question 729916: Solve: cos^2(theta)+ 2sin(theta)=2 \r
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Algebra.Com's Answer #446297 by Leaf W.(135)\"\" \"About 
You can put this solution on YOUR website!
\"cos%5E2%28theta%29+%2B+2sin%28theta%29+=+2\"
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\n" ); document.write( "Since \"sin%5E2%28theta%29+%2B+cos%5E2%28theta%29+=+1\" (a fundamental trigonometric identity), you can change this to \"cos%5E2%28theta%29+=+1+-+sin%5E2%28theta%29\" using basic algebra subtraction on both sides and substitute this into your equation for \"cos%5E2%28theta%29\".
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\n" ); document.write( "\"1+-+sin%5E2%28theta%29+%2B+2sin%28theta%29+=+2\"
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\n" ); document.write( "Move everything to the right side: \"0+=+sin%5E2%28theta%29+-+2sin%28theta%29+%2B+1\"
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\n" ); document.write( "Factor: \"0+=+%28sin%28theta%29+-+1%29%28sin%28theta%29+-+1%29\"
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\n" ); document.write( "Solve for \"sin%28theta%29\": \"sin%28theta%29+-+1+=+0\" ==> \"sin%28theta%29+=+1\"
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\n" ); document.write( "Now you have to think: for what angles is the sine equal to 1? Well, for \"pi%2F2\". However, it is also 1 at every complete revolution (every \"2pi\" from \"pi%2F2\" -- that is, \"pi%2F2+%2B+2pi%2An\", where \"n\" is an integer {think \"-3pi%2F2\", \"5pi%2F2\", etc.}). Therefore, the solution to the equation is \"theta+=+pi%2F2+%2B+2pi%2An\".
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\n" ); document.write( "IF you have a domain restriction in the problem, only include solutions that are within the domain. For example, if you have a restriction of \"0+%3C=+theta+%3C+2pi\", then your solution would be \"theta+=+pi%2F2\" only because that is the only solution in \"pi%2F2+%2B+2pi%2An\" that is between 0 and \"2pi\".
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\n" ); document.write( "I hope this helped! Good luck!
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