document.write( "Question 729767: (10/x) +3= (x+9)/(x-4)\r
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Algebra.Com's Answer #446223 by lwsshak3(11628)\"\" \"About 
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(10/x) +3= (x+9)/(x-4)
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\n" ); document.write( "(10/x) +3= (x+9)/(x-4)
\n" ); document.write( "LCD:x(x-4)
\n" ); document.write( "10x-40+3x(x-4)=x(x+9)
\n" ); document.write( "10x-40+3x^2-12x=x^2+9x
\n" ); document.write( "2x^2-11x-40=0
\n" ); document.write( "(2x+5)(x-8)=0
\n" ); document.write( "x=-5/2
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\n" ); document.write( "x=8
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\n" ); document.write( "for x=8
\n" ); document.write( "10/8+3=(8+9)/(8-4)
\n" ); document.write( "34/8=17/4
\n" ); document.write( "17/4=17/4
\n" ); document.write( "left side=right side
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\n" ); document.write( "for x=-5/2
\n" ); document.write( "10/(-5/2)+3=((-5/2)+9)/((-5/2)-4)
\n" ); document.write( "(20/-5)+3=((-5/2)+(18/2))/((-5/2)-(8/2))
\n" ); document.write( "(-4+3)=(13/2)/(-13/2)
\n" ); document.write( "-1=-1
\n" ); document.write( "left side=right side
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