document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=729754>Question 729754</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A two digit number and the resulting number when the digits are reversed are in the ratio 2:9.If the sum of the digits is 9,Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446212 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A two digit number and the resulting number when the digits are reversed are in the ratio 2:9.If the sum of the digits is 9,Find the original number.<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let u=units digit<BR>\n" );
document.write( "let t=tens digit<BR>\n" );
document.write( "t+u=9<BR>\n" );
document.write( "t=9-u<BR>\n" );
document.write( "original number=10t+u<BR>\n" );
document.write( "reversed number=10u+t<BR>\n" );
document.write( "(10t+u)/(10u+t)=2/9<BR>\n" );
document.write( "(10(9-u)+u)/(10u+9-u)=2/9<BR>\n" );
document.write( "(90-10u+u)/(10u+9-u)=2/9<BR>\n" );
document.write( "(90-9u)/(9u+9)=2/9<BR>\n" );
document.write( "810-81u=18u+18<BR>\n" );
document.write( "99u=792<BR>\n" );
document.write( "u=8<BR>\n" );
document.write( "t=9-u=1<BR>\n" );
document.write( "10t+u=10+8=18<BR>\n" );
document.write( "original number=18\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );