document.write( "Question 729754: A two digit number and the resulting number when the digits are reversed are in the ratio 2:9.If the sum of the digits is 9,Find the original number. \n" ); document.write( "
Algebra.Com's Answer #446208 by ankor@dixie-net.com(22740)\"\" \"About 
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let a = the 10's digit of the original number
\n" ); document.write( "let b = the units
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\n" ); document.write( "\"A two digit number and the resulting number when the digits are reversed are in the ratio 2:9.\"
\n" ); document.write( "\"%28%2810a%2Bb%29%29%2F%28%2810b%2Ba%29%29\" = \"2%2F9\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "9(10a+b) = 2(10b+a)
\n" ); document.write( "90a + 9b = 20b + 2a
\n" ); document.write( "90a - 2a = 20b - 9b
\n" ); document.write( "88a = 11b
\n" ); document.write( "Simplify divide by 11
\n" ); document.write( "8a = b
\n" ); document.write( ":
\n" ); document.write( "\"If the sum of the digits is 9,
\n" ); document.write( "a + b = 9
\n" ); document.write( "replace b with 8a
\n" ); document.write( "a + 8a = 9
\n" ); document.write( "9a = 9
\n" ); document.write( "a = 1
\n" ); document.write( "then
\n" ); document.write( "b = 8
\n" ); document.write( ":
\n" ); document.write( "18 is the original number
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\n" ); document.write( "Check this
\n" ); document.write( "\"18%2F81\" = \"2%2F9\"\r
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