document.write( "Question 729754: A two digit number and the resulting number when the digits are reversed are in the ratio 2:9.If the sum of the digits is 9,Find the original number. \n" ); document.write( "
Algebra.Com's Answer #446208 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let a = the 10's digit of the original number \n" ); document.write( "let b = the units \n" ); document.write( ": \n" ); document.write( "\"A two digit number and the resulting number when the digits are reversed are in the ratio 2:9.\" \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "9(10a+b) = 2(10b+a) \n" ); document.write( "90a + 9b = 20b + 2a \n" ); document.write( "90a - 2a = 20b - 9b \n" ); document.write( "88a = 11b \n" ); document.write( "Simplify divide by 11 \n" ); document.write( "8a = b \n" ); document.write( ": \n" ); document.write( "\"If the sum of the digits is 9, \n" ); document.write( "a + b = 9 \n" ); document.write( "replace b with 8a \n" ); document.write( "a + 8a = 9 \n" ); document.write( "9a = 9 \n" ); document.write( "a = 1 \n" ); document.write( "then \n" ); document.write( "b = 8 \n" ); document.write( ": \n" ); document.write( "18 is the original number \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |