document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=729746>Question 729746</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I write this in logarithimic form? 16^-1/2 = 1/4<BR>\n" );
document.write( "Can you show me how to get there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446196 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I write this in logarithimic form? 16^-1/2 = 1/4<BR>\n" );
document.write( "Given equation is written in exponential form:base(16) raised to log of the number(-1/2)=number(1/4)<BR>\n" );
document.write( "In logarithmic form: log16(1/4)=-1/2<BR>\n" );
document.write( "This reads: log of (1/4) base 16=-1/2 </SPAN>\n" );
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