document.write( "Question 729735: \"nancy and mark commute to work, traveling in opposite directions. Nancy leaves the house at 7am and averages 30 mph. mark leaves at 7:15 and averages 40 mph. at what time will they be 165 miles apart\". \n" ); document.write( "
Algebra.Com's Answer #446190 by josmiceli(19441)\"\" \"About 
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Nancy has \"+1%2F4+\" hr head start.
\n" ); document.write( "\"+d%5B1%5D+=+30%2A%281%2F4%29+=+7.5+\" mi is her head start
\n" ); document.write( "Start a stopwatch when Mark leaves and stop
\n" ); document.write( "it when they are \"+165+\" mi apart.
\n" ); document.write( "------------------------------
\n" ); document.write( "Let \"+t+\" = the time on the stopwatch when stopped
\n" ); document.write( "Let \"+d+\" = distance in miles Nancy travels in time \"+t+\"
\n" ); document.write( "\"+165+-+%28+d+%2B+7.5+%29+\" = distance in miles Mark travels in time \"+t+\"
\n" ); document.write( "------------------------------
\n" ); document.write( "Nancy's equation:
\n" ); document.write( "(1) \"+d+=++30t+\"
\n" ); document.write( "Mark's equation:
\n" ); document.write( "(2) \"+165+-+%28+d+%2B+7.5+%29+=+40t+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "(2) \"+165+-+d+-+7.5+=+40t+\"
\n" ); document.write( "(2) \"+d+%2B+40t+=+157.5+\"
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+30t+%2B+40t+=+157.5+\"
\n" ); document.write( "(2) \"+70t+=+157.5+\"
\n" ); document.write( "(2) \"+t+=+2.25+\"
\n" ); document.write( "7:15 AM + 2.25 hrs = 9:40 AM
\n" ); document.write( "They are 165 mi apart at 9:40 AM
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=++30t+\"
\n" ); document.write( "(1) \"+d+=++30%2A2.25+\"
\n" ); document.write( "(1) \"+d+=+67.5+\"
\n" ); document.write( "---------------
\n" ); document.write( "(2) \"+165+-+%28+d+%2B+7.5+%29+=+40t+\"
\n" ); document.write( "(2) \"+165+-+%28+d+%2B+7.5+%29+=+40%2A2.25+\"
\n" ); document.write( "(2) \"+165+-+7.5+-+d+=+90+\"
\n" ); document.write( "(2) \"+d+=+165+-+97.5+\"
\n" ); document.write( "(2) \"+d+=+67.5+\"
\n" ); document.write( "OK\r
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