document.write( "Question 729260: Working together, 4 skilled workers can complete a job in 5 days. However, 5 semi-skilled workers can complete the same job in 6 days. If 1 semi-skilled and 2 skilled workers work together, how long does it take for them to complete the same job? \n" ); document.write( "
Algebra.Com's Answer #446179 by ankor@dixie-net.com(22740)\"\" \"About 
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Working together, 4 skilled workers can complete a job in 5 days.
\n" ); document.write( "therefore: 4 * 5 = 20 man-days for skilled men complete the job
\n" ); document.write( ":
\n" ); document.write( " However, 5 semi-skilled workers can complete the same job in 6 days.
\n" ); document.write( "therefore: 5 * 6 = 30 man-days for semi-skilled men to complete the job
\n" ); document.write( ":
\n" ); document.write( " If 1 semi-skilled and 2 skilled workers work together, how long does it take for them to complete the same job?
\n" ); document.write( "Let d = number of days for them to complete the job.
\n" ); document.write( "Let the completed job = 1,
\n" ); document.write( "Each group will do a fraction of the job, the two fractions add up to 1
\n" ); document.write( ":
\n" ); document.write( "\"%282d%29%2F20\" + \"%281d%29%2F30\" = 1
\n" ); document.write( "multiply by 60, resulting in:
\n" ); document.write( "3(2d) + 2(1d) = 60
\n" ); document.write( "6d + 2d = 60
\n" ); document.write( "8d = 60
\n" ); document.write( "d = 60/8
\n" ); document.write( "d = 7.5 days for them to complete the job together
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