document.write( "Question 729666: The second angle of a triangular building lot is three times as large as the first.The third angle is 10 degrees more than the sum of the other two angles.What is the measurement for the third angle? \n" ); document.write( "
Algebra.Com's Answer #446172 by checkley79(3341)\"\" \"About 
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SECOND ANGLE=3F
\n" ); document.write( "THIRD ANGLE=F+S+10
\n" ); document.write( "F+S+T=180
\n" ); document.write( "F+3F+(F+S+10)=180
\n" ); document.write( "4F+F+(3F)+10=180
\n" ); document.write( "8F=180-10
\n" ); document.write( "8F=170
\n" ); document.write( "F=170/8
\n" ); document.write( "F=21.25 DEGREES FOR THE FIRST ANGLE.
\n" ); document.write( "3*21.25=63.75 DEGREES FOR THE SECOND ANGLE.
\n" ); document.write( "21.25+63.75+10=95 DEGREES FOR THE THIRD ANGLE.
\n" ); document.write( "21.25+63.75+95=180
\n" ); document.write( "180=180
\n" ); document.write( "
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