document.write( "Question 729672: Eighteen years ago a woman was 1/2 as old as her husband, while 4 years ago she was 2/3 as old as her husband. Find both of their ages now.\r
\n" ); document.write( "\n" ); document.write( "This is how far I have gotten:
\n" ); document.write( "w=wife's current age
\n" ); document.write( "h= husbands current age\r
\n" ); document.write( "\n" ); document.write( "(w-18)=(h-18)/2\r
\n" ); document.write( "\n" ); document.write( "Not even sure if I'm on the right track.....
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Algebra.Com's Answer #446166 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
w-18=(1/2)(h-18), for Eighteen years ago a woman was 1/2 as old as her husband,
\n" ); document.write( "w-4=(2/3)(h-4), for 4 years ago she was 2/3 as old as her husband.\r
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\n" ); document.write( "\n" ); document.write( "You WERE on the right track.
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