document.write( "Question 729672: Eighteen years ago a woman was 1/2 as old as her husband, while 4 years ago she was 2/3 as old as her husband. Find both of their ages now.\r
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document.write( "This is how far I have gotten:
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document.write( "w=wife's current age
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document.write( "h= husbands current age\r
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document.write( "(w-18)=(h-18)/2\r
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document.write( "Not even sure if I'm on the right track..... \n" );
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Algebra.Com's Answer #446166 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! w-18=(1/2)(h-18), for Eighteen years ago a woman was 1/2 as old as her husband, \n" ); document.write( "w-4=(2/3)(h-4), for 4 years ago she was 2/3 as old as her husband.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You WERE on the right track. \n" ); document.write( " |