document.write( "Question 729659: How many gallons of a 50% antifreeze solution must be mixed with 100 gallons of a 30% antifreeze solution to get a mixture that is 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #446162 by checkley79(3341)\"\" \"About 
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.50X+.30*100=.40(100+X)
\n" ); document.write( ".50X+30=40-.40X
\n" ); document.write( ".50X-.40X=40-30
\n" ); document.write( ".10X=10\r
\n" ); document.write( "\n" ); document.write( "X=10/.10
\n" ); document.write( "X=100 GALLONS OF 50% ARE NEEDED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".50*100+.30*100=.40(100+100)
\n" ); document.write( "50+30=.40*200
\n" ); document.write( "80=80
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