document.write( "Question 729659: How many gallons of a 50% antifreeze solution must be mixed with 100 gallons of a 30% antifreeze solution to get a mixture that is 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #446162 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .50X+.30*100=.40(100+X) \n" ); document.write( ".50X+30=40-.40X \n" ); document.write( ".50X-.40X=40-30 \n" ); document.write( ".10X=10\r \n" ); document.write( "\n" ); document.write( "X=10/.10 \n" ); document.write( "X=100 GALLONS OF 50% ARE NEEDED. \n" ); document.write( "PROOF: \n" ); document.write( ".50*100+.30*100=.40(100+100) \n" ); document.write( "50+30=.40*200 \n" ); document.write( "80=80 \n" ); document.write( " \n" ); document.write( " |