document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=729661>Question 729661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a fractions value is 3/5 if the numerator and denominator are both increased by 3 the resulting fraction equals 5/8.  What is the original fraction?  What is the proper way to solve this question? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446161 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446161\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET N BE THE MULTIPLIER.<BR>\n" );
document.write( "(3N+3)/(5N+3)=5/8 CROSS MULTIPLY<BR>\n" );
document.write( "8(3N+3)=5(5N+3)<BR>\n" );
document.write( "24N+24=25N+15<BR>\n" );
document.write( "24N-25N=15-24<BR>\n" );
document.write( "-N=-9<BR>\n" );
document.write( "N=9 ANS. FOR THE MULTIPLIER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "(3*9+3)/(5*9+3)=5/8<BR>\n" );
document.write( "(27+3)/(45+3)=5/8<BR>\n" );
document.write( "30/48=5/8 REDUCE THE LEFT FRACTION.<BR>\n" );
document.write( "5/8=5/8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );