document.write( "Question 729295: A plane can travel 975 miles with a 40 mph tailwind in the same time it can travel 800 miles with a 30 mph headwind. How fast an the plane travel with no wind resistance? \n" ); document.write( "
Algebra.Com's Answer #446151 by checkley79(3341)\"\" \"About 
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D=RT
\n" ); document.write( "975=(R+40)T
\n" ); document.write( "T=975/(R+40)
\n" ); document.write( "800=(R-30)T
\n" ); document.write( "T=800/(R-30)
\n" ); document.write( "THE TIMES ARE EQUAL SO:
\n" ); document.write( "975/(R+40)=800/(R-30)
\n" ); document.write( "975(R-30)=800(R+40)
\n" ); document.write( "975R-29,250=800R+32,000
\n" ); document.write( "975R-800R=32,000+29,250
\n" ); document.write( "175R=61,250
\n" ); document.write( "R=61,250/175
\n" ); document.write( "R=350 MPH. IN STILL AIR IS THE SPEED.
\n" ); document.write( "975=(350+40)T
\n" ); document.write( "975=390T
\n" ); document.write( "T=975/390
\n" ); document.write( "T=2.5 HOURS
\n" ); document.write( "PROOF:
\n" ); document.write( "800=(350-30)*2.5
\n" ); document.write( "800=320*2.5
\n" ); document.write( "800=800
\n" ); document.write( "
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