document.write( "Question 729295: A plane can travel 975 miles with a 40 mph tailwind in the same time it can travel 800 miles with a 30 mph headwind. How fast an the plane travel with no wind resistance? \n" ); document.write( "
Algebra.Com's Answer #446151 by checkley79(3341) ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "975=(R+40)T \n" ); document.write( "T=975/(R+40) \n" ); document.write( "800=(R-30)T \n" ); document.write( "T=800/(R-30) \n" ); document.write( "THE TIMES ARE EQUAL SO: \n" ); document.write( "975/(R+40)=800/(R-30) \n" ); document.write( "975(R-30)=800(R+40) \n" ); document.write( "975R-29,250=800R+32,000 \n" ); document.write( "975R-800R=32,000+29,250 \n" ); document.write( "175R=61,250 \n" ); document.write( "R=61,250/175 \n" ); document.write( "R=350 MPH. IN STILL AIR IS THE SPEED. \n" ); document.write( "975=(350+40)T \n" ); document.write( "975=390T \n" ); document.write( "T=975/390 \n" ); document.write( "T=2.5 HOURS \n" ); document.write( "PROOF: \n" ); document.write( "800=(350-30)*2.5 \n" ); document.write( "800=320*2.5 \n" ); document.write( "800=800 \n" ); document.write( " |