document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=729613>Question 729613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the garrison of 80 men had provision for 10 days . after 2 days some persons join the garrison and the provision lasted for 4 days how many persons join the garrison <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446106 by </B><A HREF=/tutors/aboutme.mpl?userid=mbmodak><B>mbmodak(32)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mbmodak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446106\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let us assume that each man of garrison consumes x gms provision per day					<BR>\n" );
document.write( "80 men shall consume 80*x gms per day					<BR>\n" );
document.write( "in 10 days they shall consume 80*x*10 or 800x gms					<BR>\n" );
document.write( "Now for two days 80 persons shall consume 2*80*x gms					<BR>\n" );
document.write( "therefore for remaining days the provisions in balance is  800x-160x=640x gms					<BR>\n" );
document.write( "This 640x gms quota is consumed by (80+additional men who joined after two days) in 4 days					<BR>\n" );
document.write( "Therefore No.of people=640/4=160					<BR>\n" );
document.write( "So 80 additional men joined the garrison after two days					<BR>\n" );
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